0=3x^2-16x+16

Solution for 0=3x^2-16x+16 equation:

0=3x^2-16x+16

We move all terms to the left:

0-(3x^2-16x+16)=0

We add all the numbers together, and all the variables

-(3x^2-16x+16)=0

We get rid of parentheses

-3x^2+16x-16=0

a = -3; b = 16; c = -16;
Δ = b2-4ac
Δ = 162-4·(-3)·(-16)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8}{2*-3}=\frac{-24}{-6}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8}{2*-3}=\frac{-8}{-6}
=1+1/3
$